double[,,] numbers;
To quickly determine the number of dimensions in a declared C# array, count the number of commas and add one to that total.
In the following example, I have a two-dimensional array of sales figures that represent this year's year-to-date figures and last year's totals for the same time frame. Take special note of the syntax used to instantiate the array (in the MultiDimArrayApp constructor).
using System;
class MultiDimArrayApp
{
protected int currentMonth;
protected double[,] sales;
MultiDimArrayApp()
{
currentMonth=10;
sales = new double[2, currentMonth];
for (int i = 0; i < sales.GetLength(0); i++)
{
for (int j=0; j < 10; j++)
{
sales[i,j] = (i * 100) + j;
}
}
}
protected void PrintSales()
{
for (int i = 0; i < sales.GetLength(0); i++)
{
for (int j=0; j < sales.GetLength(1); j++)
{
Console.WriteLine("[{0}][{1}]={2}", i, j, sales[i,j]);
}
}
}
public static void Main()
{
MultiDimArrayApp app = new MultiDimArrayApp();
app.PrintSales();
}
}
Running the MultiDimArrayApp example results in this output: -
[0][0]=0 [0][1]=1 [0][2]=2 [0][3]=3 [0][4]=4 [0][5]=5 [0][6]=6 [0][7]=7 [0][8]=8 [0][9]=9 [1][0]=100 [1][1]=101 [1][2]=102 [1][3]=103 [1][4]=104 [1][5]=105 [1][6]=106 [1][7]=107 [1][8]=108 [1][9]=109
Remember that in the single-dimensional array example I said the Length property will return the total number of items in the array, so in this example that return value would be 20. In the MultiDimArray.PrintSales method I used the Array.GetLength method to determine the length or upper bound of each dimension of the array. I was then able to use each specific value in the PrintSales method.
